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11 How Many Three Digit Numbers Are Divisible By 7
11 How Many Three Digit Numbers Are Divisible By 7 -
Complete step by step answer As we know the smallest 3 digit number which is divisible by 7 is 105 i e 7 15 7 15 And the largest 7 digit number can be found by dividing the largest 3 digit number by 7 and subtract the remaining remainder from the largest 3 digit number i e 999 7 7 142 5 999 7 7 142 5
Verified by Toppr Three Numbers which are divisible by 7 are 105 112 119 994 which forms an A P first term of this A P a1 105 second term of this A P is a2 112 common difference of this A P is d a2 a1 112 105 7 nth term of this A P is given by
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Total 5 digit Numbers Divisible By 4 Can Be Formed Using 0 1 2 3 4 5
Total 5 digit Numbers Divisible By 4 Can Be Formed Using 0 1 2 3 4 5
The first three digit number which is divisible by 7 is 105 and the last three digit number which is divisible by 7 is 994 This is an A P in which a 105 d 7 and l 994 Let the number of terms be n then Tn 994 T n 994 Therefore there are 128 three digit numbers which are divisible by 7
How many three digit numbers are divisible by 7 Answer Step 1 The smallest three digit number is 100 The largest three digit number is 999 Step 2 Let us find number of numbers divisible by 7 from 1 to 999 Divide 999 by 7 142 71 Therefore number of numbers divisible by 7 from 1 to 999 is 142 Step 3
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Find The Sum Of All Three Digit Numbers Divisible By 7 YouTube
Find The Sum Of All Three Digit Numbers Divisible By 7 YouTube
Flexi Says Let s find the first and last three digit numbers divisible by 7 First 100 7 15 so 15 7 105 Last 999 7 142 so 142 7 994 Now we can find the total number of three digit numbers divisible by 7 142 15 1 128 There are 128 three digit numbers divisible by 7 Just like a lucky 7 jackpot
Answer 128 three digit numbers are divisible by 7 Now let s find out how we can reach this answer by following the abovementioned steps So the first 3 digit number divisible by 7 is 105 and the last 3 digit divisible by 7 is 994 Hence the sequence of numbers will be something like 105 112 994
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https://www.toppr.com/ask/question/how-many-three...
Verified by Toppr Three Numbers which are divisible by 7 are 105 112 119 994 which forms an A P first term of this A P a1 105 second term of this A P is a2 112 common difference of this A P is d a2 a1 112 105 7 nth term of this A P is given by
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Clearly 999 5 994 is the maximum possible three digit number that is divisible by 7 Hence the final sequence is as follows 105 112 119 994 Let 994 be the n th term of this A P a 105 d 7 a 994 n We know that the n th term of an A P is a a n 1 d 994 105 n 1 7 889 n 1 7 n 1 889 7 n
Verified by Toppr Three Numbers which are divisible by 7 are 105 112 119 994 which forms an A P first term of this A P a1 105 second term of this A P is a2 112 common difference of this A P is d a2 a1 112 105 7 nth term of this A P is given by
Clearly 999 5 994 is the maximum possible three digit number that is divisible by 7 Hence the final sequence is as follows 105 112 119 994 Let 994 be the n th term of this A P a 105 d 7 a 994 n We know that the n th term of an A P is a a n 1 d 994 105 n 1 7 889 n 1 7 n 1 889 7 n
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